Optimal. Leaf size=112 \[ -\frac{a^2 \tan ^5(c+d x)}{5 d}+\frac{i a^2 \tan ^4(c+d x)}{2 d}+\frac{2 a^2 \tan ^3(c+d x)}{3 d}-\frac{i a^2 \tan ^2(c+d x)}{d}-\frac{2 a^2 \tan (c+d x)}{d}-\frac{2 i a^2 \log (\cos (c+d x))}{d}+2 a^2 x \]
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Rubi [A] time = 0.142858, antiderivative size = 112, normalized size of antiderivative = 1., number of steps used = 6, number of rules used = 4, integrand size = 24, \(\frac{\text{number of rules}}{\text{integrand size}}\) = 0.167, Rules used = {3543, 3528, 3525, 3475} \[ -\frac{a^2 \tan ^5(c+d x)}{5 d}+\frac{i a^2 \tan ^4(c+d x)}{2 d}+\frac{2 a^2 \tan ^3(c+d x)}{3 d}-\frac{i a^2 \tan ^2(c+d x)}{d}-\frac{2 a^2 \tan (c+d x)}{d}-\frac{2 i a^2 \log (\cos (c+d x))}{d}+2 a^2 x \]
Antiderivative was successfully verified.
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Rule 3543
Rule 3528
Rule 3525
Rule 3475
Rubi steps
\begin{align*} \int \tan ^4(c+d x) (a+i a \tan (c+d x))^2 \, dx &=-\frac{a^2 \tan ^5(c+d x)}{5 d}+\int \tan ^4(c+d x) \left (2 a^2+2 i a^2 \tan (c+d x)\right ) \, dx\\ &=\frac{i a^2 \tan ^4(c+d x)}{2 d}-\frac{a^2 \tan ^5(c+d x)}{5 d}+\int \tan ^3(c+d x) \left (-2 i a^2+2 a^2 \tan (c+d x)\right ) \, dx\\ &=\frac{2 a^2 \tan ^3(c+d x)}{3 d}+\frac{i a^2 \tan ^4(c+d x)}{2 d}-\frac{a^2 \tan ^5(c+d x)}{5 d}+\int \tan ^2(c+d x) \left (-2 a^2-2 i a^2 \tan (c+d x)\right ) \, dx\\ &=-\frac{i a^2 \tan ^2(c+d x)}{d}+\frac{2 a^2 \tan ^3(c+d x)}{3 d}+\frac{i a^2 \tan ^4(c+d x)}{2 d}-\frac{a^2 \tan ^5(c+d x)}{5 d}+\int \tan (c+d x) \left (2 i a^2-2 a^2 \tan (c+d x)\right ) \, dx\\ &=2 a^2 x-\frac{2 a^2 \tan (c+d x)}{d}-\frac{i a^2 \tan ^2(c+d x)}{d}+\frac{2 a^2 \tan ^3(c+d x)}{3 d}+\frac{i a^2 \tan ^4(c+d x)}{2 d}-\frac{a^2 \tan ^5(c+d x)}{5 d}+\left (2 i a^2\right ) \int \tan (c+d x) \, dx\\ &=2 a^2 x-\frac{2 i a^2 \log (\cos (c+d x))}{d}-\frac{2 a^2 \tan (c+d x)}{d}-\frac{i a^2 \tan ^2(c+d x)}{d}+\frac{2 a^2 \tan ^3(c+d x)}{3 d}+\frac{i a^2 \tan ^4(c+d x)}{2 d}-\frac{a^2 \tan ^5(c+d x)}{5 d}\\ \end{align*}
Mathematica [A] time = 0.291767, size = 108, normalized size = 0.96 \[ -\frac{a^2 \tan ^5(c+d x)}{5 d}+\frac{2 a^2 \tan ^3(c+d x)}{3 d}+\frac{2 a^2 \tan ^{-1}(\tan (c+d x))}{d}-\frac{2 a^2 \tan (c+d x)}{d}-\frac{i a^2 \left (-\tan ^4(c+d x)+2 \tan ^2(c+d x)+4 \log (\cos (c+d x))\right )}{2 d} \]
Antiderivative was successfully verified.
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Maple [A] time = 0.004, size = 117, normalized size = 1. \begin{align*} -2\,{\frac{{a}^{2}\tan \left ( dx+c \right ) }{d}}-{\frac{{a}^{2} \left ( \tan \left ( dx+c \right ) \right ) ^{5}}{5\,d}}+{\frac{{\frac{i}{2}}{a}^{2} \left ( \tan \left ( dx+c \right ) \right ) ^{4}}{d}}+{\frac{2\,{a}^{2} \left ( \tan \left ( dx+c \right ) \right ) ^{3}}{3\,d}}-{\frac{i{a}^{2} \left ( \tan \left ( dx+c \right ) \right ) ^{2}}{d}}+{\frac{i{a}^{2}\ln \left ( 1+ \left ( \tan \left ( dx+c \right ) \right ) ^{2} \right ) }{d}}+2\,{\frac{{a}^{2}\arctan \left ( \tan \left ( dx+c \right ) \right ) }{d}} \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
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Maxima [A] time = 2.15202, size = 128, normalized size = 1.14 \begin{align*} -\frac{6 \, a^{2} \tan \left (d x + c\right )^{5} - 15 i \, a^{2} \tan \left (d x + c\right )^{4} - 20 \, a^{2} \tan \left (d x + c\right )^{3} + 30 i \, a^{2} \tan \left (d x + c\right )^{2} - 60 \,{\left (d x + c\right )} a^{2} - 30 i \, a^{2} \log \left (\tan \left (d x + c\right )^{2} + 1\right ) + 60 \, a^{2} \tan \left (d x + c\right )}{30 \, d} \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
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Fricas [B] time = 2.15081, size = 656, normalized size = 5.86 \begin{align*} \frac{-270 i \, a^{2} e^{\left (8 i \, d x + 8 i \, c\right )} - 600 i \, a^{2} e^{\left (6 i \, d x + 6 i \, c\right )} - 740 i \, a^{2} e^{\left (4 i \, d x + 4 i \, c\right )} - 400 i \, a^{2} e^{\left (2 i \, d x + 2 i \, c\right )} - 86 i \, a^{2} +{\left (-30 i \, a^{2} e^{\left (10 i \, d x + 10 i \, c\right )} - 150 i \, a^{2} e^{\left (8 i \, d x + 8 i \, c\right )} - 300 i \, a^{2} e^{\left (6 i \, d x + 6 i \, c\right )} - 300 i \, a^{2} e^{\left (4 i \, d x + 4 i \, c\right )} - 150 i \, a^{2} e^{\left (2 i \, d x + 2 i \, c\right )} - 30 i \, a^{2}\right )} \log \left (e^{\left (2 i \, d x + 2 i \, c\right )} + 1\right )}{15 \,{\left (d e^{\left (10 i \, d x + 10 i \, c\right )} + 5 \, d e^{\left (8 i \, d x + 8 i \, c\right )} + 10 \, d e^{\left (6 i \, d x + 6 i \, c\right )} + 10 \, d e^{\left (4 i \, d x + 4 i \, c\right )} + 5 \, d e^{\left (2 i \, d x + 2 i \, c\right )} + d\right )}} \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
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Sympy [B] time = 6.15784, size = 228, normalized size = 2.04 \begin{align*} - \frac{2 i a^{2} \log{\left (e^{2 i d x} + e^{- 2 i c} \right )}}{d} + \frac{- \frac{18 i a^{2} e^{- 2 i c} e^{8 i d x}}{d} - \frac{40 i a^{2} e^{- 4 i c} e^{6 i d x}}{d} - \frac{148 i a^{2} e^{- 6 i c} e^{4 i d x}}{3 d} - \frac{80 i a^{2} e^{- 8 i c} e^{2 i d x}}{3 d} - \frac{86 i a^{2} e^{- 10 i c}}{15 d}}{e^{10 i d x} + 5 e^{- 2 i c} e^{8 i d x} + 10 e^{- 4 i c} e^{6 i d x} + 10 e^{- 6 i c} e^{4 i d x} + 5 e^{- 8 i c} e^{2 i d x} + e^{- 10 i c}} \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
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Giac [B] time = 2.54561, size = 370, normalized size = 3.3 \begin{align*} \frac{-30 i \, a^{2} e^{\left (10 i \, d x + 10 i \, c\right )} \log \left (e^{\left (2 i \, d x + 2 i \, c\right )} + 1\right ) - 150 i \, a^{2} e^{\left (8 i \, d x + 8 i \, c\right )} \log \left (e^{\left (2 i \, d x + 2 i \, c\right )} + 1\right ) - 300 i \, a^{2} e^{\left (6 i \, d x + 6 i \, c\right )} \log \left (e^{\left (2 i \, d x + 2 i \, c\right )} + 1\right ) - 300 i \, a^{2} e^{\left (4 i \, d x + 4 i \, c\right )} \log \left (e^{\left (2 i \, d x + 2 i \, c\right )} + 1\right ) - 150 i \, a^{2} e^{\left (2 i \, d x + 2 i \, c\right )} \log \left (e^{\left (2 i \, d x + 2 i \, c\right )} + 1\right ) - 270 i \, a^{2} e^{\left (8 i \, d x + 8 i \, c\right )} - 600 i \, a^{2} e^{\left (6 i \, d x + 6 i \, c\right )} - 740 i \, a^{2} e^{\left (4 i \, d x + 4 i \, c\right )} - 400 i \, a^{2} e^{\left (2 i \, d x + 2 i \, c\right )} - 30 i \, a^{2} \log \left (e^{\left (2 i \, d x + 2 i \, c\right )} + 1\right ) - 86 i \, a^{2}}{15 \,{\left (d e^{\left (10 i \, d x + 10 i \, c\right )} + 5 \, d e^{\left (8 i \, d x + 8 i \, c\right )} + 10 \, d e^{\left (6 i \, d x + 6 i \, c\right )} + 10 \, d e^{\left (4 i \, d x + 4 i \, c\right )} + 5 \, d e^{\left (2 i \, d x + 2 i \, c\right )} + d\right )}} \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
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